Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. See it on Leetcode
Example 1
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Input: [7, 1, 5, 3, 6, 4]
Output: 5
max. difference = 6-1 = 5
Not 7-1 = 6, as selling price needs to be larger than buying price.
Example 2
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Input: [7, 6, 4, 3, 1]
Output: 0
In thiscase, no transaction is done, i.e. max profit = 0.
Hint
Brute force approach may result in Time Limit Exceeded. Try greedy approach.
Solution in Java and Golang
java
go
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publicclassSolution{ publicintmaxProfit(int[] prices){ int minPrice = Integer.MAX_VALUE; int maxProfit = 0; for (int i : prices) { if (i < minPrice) { minPrice = i; } elseif (i - minPrice > maxProfit) { maxProfit = i - minPrice; } } return maxProfit; } }